16/(x^2+8x+64)=8

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Solution for 16/(x^2+8x+64)=8 equation: 


D( x )

x^2+8*x+64 = 0

x^2+8*x+64 = 0

x^2+8*x+64 = 0

x^2+8*x+64 = 0

DELTA = 8^2-(1*4*64)

DELTA = -192

DELTA < 0

x in (-oo:+oo)

16/(x^2+8*x+64) = 8 // - 8

16/(x^2+8*x+64)-8 = 0

x^2+8*x+64 = 0

x^2+8*x+64 = 0

x^2+8*x+64 = 0

DELTA = 8^2-(1*4*64)

DELTA = -192

DELTA < 0

1 = 0

16-8 = 0

16-8 = 0

8 = 0

8 = 0

x belongs to the empty set

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